1、第一章4 4.3、4.4一、选择题1sin(390)的值为()ABCD答案D解析sin(390)sin(36030)sin(30)sin30.2已知cos(x),则sinx的值为()AB CD答案B解析cos(x)sinx,sinx.3在ABC中,cos(AB)的值等于()AcosCBcosC CsinCDsinC答案B解析cos(AB)cos(180C)cosC4若sin(),则sin(4)的值是()AB CD答案B解析sin(),sin.sin(4)sin()sin.5已知sin(),则cos()的值等于()AB CD答案C解析cos()sin()sin()sin().6已知sin10k,
2、则cos620的值等于()AkBkCkD不能确定答案B解析cos620cos(360260)cos260cos(18080)cos80sin10k.二、填空题7sin(1200)cos1290cos(1020)sin(1050)_.答案1解析原式sin1200cos1290cos1020sin1050sin(607180)cos(307180)cos(603360)sin(303360)sin(60)(cos30)cos(60)sin(30)()()1.8已知,则cos(3)_.答案解析,cos.cos(3)cos()cos.三、解答题9已知cos(75),求cos(105)sin(15)的值
3、解析(105)(75)180,(15)(75)90,cos(105)cos180(75)cos(75),sin(15)sin90(75)cos(75).cos(105)sin(15)0.10化简求值:.解析原式1.一、选择题1已知函数f(x)cos,则下列等式成立的是()Af(2x)f(x)Bf(2x)f(x)Cf(x)f(x)Df(x)f(x)答案D解析f(x)cos,f(x)cos()cos,C不对;又f(2x)coscos()cosf(x)A不对f(2x)coscos()cosf(x),B不对,故选D2若sin()cos()m,则cos()2sin(6)的值为()AmBm CmDm答案B
4、解析sin()cos()m,sinsin2sinm,sin.cos()2sin(6)sin2sin3sinm.二、填空题3若|cos|cos(),则角的集合为_答案解析因为|cos|cos()cos,所以|cos|cos,所以cos0,所以角的集合为.4若P(4,3)是角终边上一点,则的值为_答案解析P(4,3)在角的终边上,|OP|5,sin,cos.原式.三、解答题5已知f().(1)化简f();(2)若,求f()的值;(3)若cos(),求f()的值解析(1)f()cos.(2)f()cos()cos(62)coscos.(3)cos(),cos().sin.由,cos.f()cos.6求证:对任意的整数k,1.证明左边(1)当k为偶数时,设k2n(nZ),左边1.(2)当k为奇数时,设k2n1(nZ),同理可得左边1,综上原等式成立7已知函数f(x)asin(x)bcos(x),其中a,b,都是非零实数,又知f(2015)1,求f(2016)的值解析f(2015)asin(2015)bcos(2015)asin(2014)bcos(2014)asin()bcos()asinbcos(asinbcos)f(2015)1,asinbcos1,f(2016)asin(2016)bcos(2016)asinbcos1.