1、温馨提示： 此套题为Word版，请按住Ctrl,滑动鼠标滚轴，调节合适的观看比例，答案解析附后。关闭Word文档返回原板块。练 考题预测全过关1.(2019全国卷)已知集合U=1,2,3,4,5,6,7,A=2,3,4,5,B=2,3,6,7,则BUA=()A.1,6B.1,7C.6,7D.1,6,7【解析】选C.由已知得UA=1,6,7,所以BUA=6,7,故选C.2.(2019全国卷)设集合A=x|x2-5x+60,B=x|x-10,则AB=()A.(-,1)B.(-2,1)C.(-3,-1)D.(3,+)【解析】选A.解得集合A=x|x3,集合B=x|x1.结合数轴可得x1.3.已知集合
2、A=xN|x3,B=x|x=a-b,aA,bA,则AB=()A.1,2B.-2,-1,1,2C.1D.0,1,2【解析】选D.由A=xN|x3,B=x|x=a-b,aA,bA,得A=0,1,2,B=-2,-1,0,1,2,则AB=0,1,2.4.已知集合A=1,2,3,B=y|y=2x+1,xA,则AB=()A.1,3,5,7B.1,2,3C.1,2,3,4D.1,2,3,5,7【解析】选D.由题意,集合A=1,2,3,B=y|y=2x+1,xA=3,5,7,所以AB=1,2,3,5,7.5.设集合A=,B=x|x|1,则AB=()A.B.x|-1x2C.x|-1x2且x1D.x|-1x2【解析】选D.易得A=,B=x|-1x1,所以AB=x|-1x2.6.设集合A=x|x2a,B=x|x2,若AB=A,则实数a的取值范围是_.【解析】由AB=AAB,所以当A=时,满足AB,此时不等式x20时,A=x|-x0,由AB可知20a4,综上可知实数a的取值范围是a4.答案:a4关闭Word文档返回原板块
