第五章5.55.5.1第1课时1cos 20(B)Acos 30cos 10sin 30sin 10Bcos 30cos 10sin 30sin 10Csin 30cos 10sin 10cos 30Dcos 30cos10sin 30cos 10解析cos 20cos(3010)cos 30cos 10sin 30sin 10,故选B2cos(85)cos(35)sin(85)sin(35)的值为(A)A BCD解析原式cos(85)(35)cos(120)cos 120cos 60,故选A3已知sin ,(,),则sin()_.解析sin()cos()coscos sinsin .4sin()sincos()cos_cos_.解析原式cos()cos()cos.5已知sin(),(,),求sin()的值解析sin()cos,cos.又(,),sin,sin()cos()cos()coscossinsin()().